If the sum of \(n\) terms of an AP is \(cn^2\), then the sum of squares of these \(n\) terms is

If the sum of (n) terms of an AP is (cn^2), then the sum of squares of these (n) terms is

(a)  (frac{n(4n^2-1)c^2}{6})

(b)  (frac{n(4n^2+1)c^2}{3})

(c)  (frac{n(4n^2-1)c^2}{3})

(d)  (frac{n(4n^2+1)c^2}{6})