If \(\log_4A=\log_6B=\log_9(A+B)\), then the value of \(\frac{B}{A}\) is

If (log_4A=log_6B=log_9(A+B)), then the value of (frac{B}{A}) is

(a) (frac{sqrt{5}-1}{4})

(b) (frac{sqrt{5}-1}{2})

(c) (frac{sqrt{5}+1}{4})

(d) (frac{sqrt{5}+1}{2})